x^2+7x+8=2x2+7x+8=2

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Solution for x^2+7x+8=2x2+7x+8=2 equation: 



x^2+7x+8=2x^2+7x+8=2

We move all terms to the left:

x^2+7x+8-(2x^2+7x+8)=0

We get rid of parentheses

x^2-2x^2+7x-7x-8+8=0

We add all the numbers together, and all the variables

-1x^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-2}=0$

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